2x^2-32x+30=0

Solution for 2x^2-32x+30=0 equation:

2x^2-32x+30=0

a = 2; b = -32; c = +30;
Δ = b2-4ac
Δ = -322-4·2·30
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-28}{2*2}=\frac{4}{4}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+28}{2*2}=\frac{60}{4}
=15
$